The dimension for kinematic viscosity is

\frac{L}{M T}

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\frac{L}{T^{2}}

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\frac{L^{2}}{T}

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\frac{M L}{T}

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Solution

The correct option is C $\frac{L^{2}}{T}$
$The SI unit of kinematic viscosity is m^{2} / s$

$∴ Dimension of kinematic viscosity [v] = L^{2} / T$

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The dimensional formula for coefficient of kinematics viscosity is

(v)

(μ)

ν

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