The dimension of magnetic field in M- L- T and C -coulomb- is given as-1- MT2C ndash-2 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -2- MT ndash-1C ndash-1 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp-3- MT ndash-2C ndash-1 nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp-4- MLT ndash-1C ndash-1 nbsp-

Dear Student , Lorentz force =| F |=| qv nbsp; times; nbsp;B nbsp;| [B] = [F]/[q][v] = MLT 2/C times; nbsp;LT 1 = [MT 1C 1] Regards ...

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Byju's Answer

Standard XII

Physics

Ampere's Circuital Law

The dimension...

Question

The dimension of magnetic field in M, L, T and C (coulomb) is given as
(1) MT²C^–2 (2) MT^–1C^–1 (3) MT^–2C^–1 (4) MLT^–1C^–1

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Solution

Dear Student ,
Lorentz force =| F |=| qv × B |

[B] = [F]/[q][v]

= MLT-2/C × LT-1

= [MT-1C-1]

Regards

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The dimension of magnetic field in M, L, T and C (coulomb) is given as (1) MT2C–2 (2) MT–1C–1 (3) MT–2C–1 (4) MLT–1C–1

Dear Student , Lorentz force =| F |=| qv × B | [B] = [F]/[q][v] = MLT-2/C × LT-1 = [MT-1C-1] Regards

The dimension of magnetic field in M, L, T and C (coulomb) is given as
(1) MT²C^–2 (2) MT^–1C^–1 (3) MT^–2C^–1 (4) MLT^–1C^–1

Dear Student ,
Lorentz force =| F |=| qv × B |

[B] = [F]/[q][v]

= MLT-2/C × LT-1

= [MT-1C-1]

Regards