The dimension of magnetic induction in $M, L, T$ and $C$ (Coloumb) is given as:

{M T}^{- 1} C^{- 1}

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{M T}^{- 2} C^{- 1}

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{M L T}^{- 1} C^{- 1}

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{M T}^{2} C^{- 2}

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Solution

The correct option is B ${M T}^{- 1} C^{- 1}$
$F o r c e = B i l = M^{1} L^{1} T^{- 2}$

$B = \frac{M^{1} L^{1} T^{- 2}}{I^{1} L^{1}} = M^{1} I^{- 1} T^{- 2}$

$C = C h a r g e = I^{1} T^{1}$

$S o, B = M^{1} C^{- 1} T^{- 1}$

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The dimension of magnetic induction in M,L,T and C (Coloumb) is given as:

The correct option is B MT−1C−1Force=Bil=M1L1T−2B=M1L1T−2I1L1=M1I−1T−2C=Charge=I1T1So,B=M1C−1T−1

The dimension of magnetic induction in $M, L, T$ and $C$ (Coloumb) is given as:

The correct option is B ${M T}^{- 1} C^{- 1}$
$F o r c e = B i l = M^{1} L^{1} T^{- 2}$

$B = \frac{M^{1} L^{1} T^{- 2}}{I^{1} L^{1}} = M^{1} I^{- 1} T^{- 2}$

$C = C h a r g e = I^{1} T^{1}$

$S o, B = M^{1} C^{- 1} T^{- 1}$