The dimension of the ratio of magnetic flux and the resistance is equal to that of:

induced emf

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charge

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inductance

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current

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Solution

The correct option is C charge
Dimension of magnetic flux $= [M L^{2} T^{- 2} A^{- 1}]$

Dimension of resistance $= M L^{2} T^{- 3} A^{- 2}]$

Therefore,

$\frac{[M a g n e t i c f l u x]}{[R e s i s t a n c e]} = \frac{[M L^{2} T^{- 2} A^{- 1}]}{[M L^{2} T^{- 3} A^{- 2}]} = [A T] = C h a r g e$

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\frac{m a g n e t i c f l u x}{e l e c t r i c f l u x}

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