The dimension of universal gravitational constant is :

[M^{- 2} L^{- 3} T^{- 2}]

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[M^{- 2} L^{2} T^{- 1}]

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[M^{- 1} L^{3} T^{- 2}]

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[M L^{2} T^{- 1}]

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Solution

The correct option is C $[M^{- 1} L^{3} T^{- 2}]$
$F = \frac{G m_{1} m_{2}}{r^{2}}$
$\Rightarrow G = \frac{F r^{2}}{m_{1} m_{2}} = \frac{[M L T^{- 2}] [L^{2}]}{[M^{2}]}$
$= [M^{- 1} L^{3} T^{- 2}]$ .

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The dimension of universal gravitational constant is :

The correct option is C [M−1L3T−2]F=Gm1m2r2⇒G=Fr2m1m2=[MLT−2][L2][M2]=[M−1L3T−2].

The correct option is C $[M^{- 1} L^{3} T^{- 2}]$
$F = \frac{G m_{1} m_{2}}{r^{2}}$
$\Rightarrow G = \frac{F r^{2}}{m_{1} m_{2}} = \frac{[M L T^{- 2}] [L^{2}]}{[M^{2}]}$
$= [M^{- 1} L^{3} T^{- 2}]$ .