Question

The dimensional formula for electric flux density is given by

• A. $\left[ML{T}^{-3}A-1\right]$
• B. $\left[ML{T}^{3}A-1\right]$
• C. $\left[ML{T}^{-3}A1\right]$
• D. $\left[ML{T}^{3}A1\right]$

Answer 1

The correct option is A $\left[ML{T}^{-3}A-1\right]$

$\varphi =\overrightarrow{E}.\overrightarrow{A}$

Hence, unit is $\left(N/C\right).m^2$

Dimension of electric flux$\left[ML{T}^{-2}\right]\left[A^{-1}{T}^{-1}\right]\left[L^2\right]$

$=\left[M{L}^3{T}^{-3}{A}^{-1}\right]$

Electric flux density is flux per unit area.Hence, its dimension is same as that of electric field.

Dimension of electric flux density is given by $\left[ML{T}^{-3}{A}^{-1}\right]$

Answer-(A)