The dimensional formula for electric intensity is

[M^{1} L^{1} T^{3} A^{- 1}]

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[M L^{- 1} T^{3} A^{1}]

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[M^{1} L^{1} T^{- 3} A^{- 1}]

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[M^{1} L^{2} T^{1} A^{1}]

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Solution

The correct option is C $[M^{1} L^{1} T^{- 3} A^{- 1}]$
Since $E = \frac{F}{q}, [E] = \frac{[M^{1} L^{1} T^{- 2}]}{[A T]} = [M^{1} L^{1} T^{3} A^{- 1}]$

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Similar questions

Q. The dimensional formula of a physical quantity is

M^{1} L^{2} T^{3} I^{- 1}

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Let L₁ and L₂ be two non-vertical lines with slopes m₁ and m₂ respectively. If α₁ and α₂ are the inclinations of lines L₁ and L₂, respectively. the acute angle (say θ) between lines L1 and L2 , is given by

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Q. If two lines have direction cosines

l_{1}, m_{1}, n_{1}

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then the condition for these lines being parallel to each other would be -

[M^{1} L^{2} T^{- 3} A^{- 2}]

is the dimensional formula of :

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The dimensional formula for electric intensity is

The correct option is C [M1L1T−3A−1]Since E=Fq,[E]=[M1L1T−2][AT]=[M1L1T3A−1]

The correct option is C $[M^{1} L^{1} T^{- 3} A^{- 1}]$
Since $E = \frac{F}{q}, [E] = \frac{[M^{1} L^{1} T^{- 2}]}{[A T]} = [M^{1} L^{1} T^{3} A^{- 1}]$