The dimensional formula for magnetic flux is

[M L^{2} T^{- 2} A^{- 1}]

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[M L^{3} T^{- 2} A^{- 2}]

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[M^{0} L^{2} T^{- 2} A^{- 2}]

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[M L^{2} T^{- 1} A^{2}]

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Solution

The correct option is B $[M L^{2} T^{- 2} A^{- 1}]$
We know that

$F = q v B sin θ$

$B = \frac{F}{q v sin θ}$

$[B] = \frac{[M L T^{- 2}]}{[L T^{- 1}] [A T]}$

$[B] = [M L^{0} T^{- 2} A^{- 1}]$

We know that the magnetic flux

$= B A$

Therefore, the dimension formula

$= [M L^{0} T^{- 2} A^{- 1}] [L^{2}]$

$= [M L^{2} T^{- 2} A^{- 1}]$

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