Question

The dimensional formula for magnetic flux is

• A. $\left[M{L}^2{T}^{-2}{A}^{-1}\right]$
• B. $\left[M{L}^3{T}^{-2}{A}^{-2}\right]$
• C. $\left[M^0{L}^2{T}^{-2}{A}^{-2}\right]$
• D. $\left[M{L}^2{T}^{-1}{A}^2\right]$

Answer 1

Answer: (A)

$\left[M{L}^2{T}^{-2}{A}^{-1}\right]$

We know that

$F=qvB\sin \theta$

$B=\frac{F}{qv\sin \theta }$

$\left[B\right]=\frac{\left[ML{T}^{-2}\right]}{\left[L{T}^{-1}\right]\left[AT\right]}$

$\left[B\right]=\left[M{L}^0{T}^{-2}{A}^{-1}\right]$

We know that the magnetic flux

$=BA$

Therefore, the dimension formula

$=\left[M{L}^0{T}^{-2}{A}^{-1}\right]\left[L^2\right]$

$=\left[M{L}^2{T}^{-2}{A}^{-1}\right]$