The dimensional formula for Magnetic induction is :

{M T}^{- 1} A^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{M T}^{- 2} A^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{M L A}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{M T}^{- 2} A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B ${M T}^{- 2} A^{- 1}$
$F = B Q V$
Dimension of B will be $\frac{M L T^{- 2}}{A T L T^{- 1}} = M L^{0} T^{- 2} A^{- 1}$

Suggest Corrections

Similar questions

Q. A toroid with mean radius of 20 cm & 490 turns is filled with powder steel (having magnetic susceptibility 999). If 4.0 A current flows in toroid windings, then find the value of

B

inside the toroid ?

A solenoid has a length 1 m and inner diameter 4 cm and it carries a current of 5 A. It consists of five close packed layers, each with 800 turns along its length. The magnitude of the magnetic field at the centre is nearly equal to

Q. A good example of a volcano is

a. Mt. Fujiyama
b. Mt. Everest
c. Mt. K2
d. Mt. Nanda Devi

Q. Which of the following is not an example of a volcanic mountain?

a. Mt. Fujiyama
b. Mt. Kanchenjanga
c. Mt. Kalimanjaro
d. Mt. Vesuvius

Q. The dimensional formula for the product of two physical quantities

P

and

Q

{M L}^{2} T^{- 2}

The dimensional formula of

\frac{P}{Q}

{M T}^{- 2}

. Then P and Q respectively are:

Join BYJU'S Learning Program

The dimensional formula for Magnetic induction is :

The correct option is B MT−2A−1F=BQVDimension of B will be MLT−2ATLT−1=ML0T−2A−1

The correct option is B ${M T}^{- 2} A^{- 1}$
$F = B Q V$
Dimension of B will be $\frac{M L T^{- 2}}{A T L T^{- 1}} = M L^{0} T^{- 2} A^{- 1}$