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Byju's Answer
Standard XII
Physics
Dimensional Analysis
The dimension...
Question
The dimensional formula for magnetic permeability
μ
is
A
[
M
L
T
−
2
A
−
2
]
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B
[
M
0
L
−
1
T
]
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C
[
M
0
L
2
T
−
2
A
−
2
]
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D
[
M
L
2
T
−
2
A
−
2
]
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Solution
The correct option is
A
[
M
L
T
−
2
A
−
2
]
Magnetic permeability
is a constant of proportionality that exists between
magnetic
induction and
magnetic
field intensity.
In SI units
, permeability is measured in henries
per meter
H
/
m
or
H
m
−
1
.
Henry has the dimensions of
[
M
L
2
T
−
2
A
−
2
]
.
Dimensions for magnetic permeability will be
[
M
L
2
T
−
2
A
−
2
]
/
[
L
]
=
[
M
L
T
−
2
A
−
2
]
Suggest Corrections
2
Similar questions
Q.
Match the following:
Table-1 Table-2
(
A
)
L
(
P
)
[
M
0
L
0
T
−
2
A
0
]
(
B
)
Magnetic flux
(
Q
)
[
M
L
2
T
−
2
A
−
1
]
(
C
)
L
C
(
R
)
[
M
L
2
T
−
2
A
−
2
]
(
D
)
C
R
2
(
S
)
None
Q.
If electronic charge
e
, electron mass
m
, speed of light in vaccum
c
and Plank's constant
h
are taken as fundamental quantities, the permeability of vaccum
μ
0
can be expressed in units of
Hint:
[
h
]
=
[
M
L
2
T
−
1
]
,
[
μ
0
]
=
[
M
L
T
−
2
A
−
2
]
Q.
M
L
2
T
−
2
is the dimensional formula for
Q.
What is the dimensional formula of angular momentum
L
?
L
=
r
p
sin
θ
, where
r
is the position and
P
is momentum.
Q.
If electronic charge
e
, electron mass
m
, speed of light in vaccum
c
and Plank's constant
h
are taken as fundamental quantities, the permeability of vaccum
μ
0
can be expressed in units of
Hint:
[
h
]
=
[
M
L
2
T
−
1
]
,
[
μ
0
]
=
[
M
L
T
−
2
A
−
2
]
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