The dimensional formula for moment of couple is :

[M^{1} L^{2} T^{- 1}]

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[M^{1} L^{2} T^{- 2}]

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[M^{- 1} L^{2} T^{- 2}]

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[M^{1} L^{1} T^{- 2}]

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Solution

The correct option is B $[M^{1} L^{2} T^{- 2}]$
Moment of a couple is calculated by multiplying the size of one of the force (F) by the perpendicular distance between the two forces.
Thus the units are that of $N m$ and dimensions are $[(M^{1} L T^{- 2}) (L)] = [M^{1} L^{2} T^{- 2}]$

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