Question

The dimensional formula for plank's constant and angular momentum are

• A. $\left[M{L}^2{T}^{-2}\right]and\left[ML{T}^{-1}\right]$
• B. $\left[M{L}^2{T}^{-1}\right]and\left[M{L}^2{T}^{-1}\right]$
• C. $\left[M{L}^3{T}^1\right]and\left[M{L}^2{T}^{-2}\right]$
• D. $\left[M{L}^2{T}^{-1}\right]and\left[M{L}^2{T}^{-2}\right]$

Answer 1

The correct option is B $\left[M{L}^2{T}^{-1}\right]and\left[M{L}^2{T}^{-1}\right]$

Planck's constant, symbolized h, relates the energy in one quantum (photon) of electromagnetic radiation to the frequency of that radiation.

$h=\frac{E}{v}=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[T^{-1}\right]}=\left[M{L}^2{T}^{-1}\right]$

Angular momentum $=$ Moment of inertia $\times$ Angular velocity (Angular momentum)

$=\left[M{L}^2\right]\left[T^{-1}\right]=\left[M{L}^2{T}^{-1}\right]$

So, correct answer is option (B).