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Dimensional Analysis

The dimension...

Question

The dimensional formula for potential energy is:

A

M^{2} L^{2} T^{- 2}

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B

M^{1} L^{- 2} T^{- 2}

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C

M^{1} L^{2} T^{- 2}

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D

M^{1} L^{2} T^{- 3}

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Solution

The correct option is C $M^{1} L^{2} T^{- 2}$
Potential energy $= [m g h] = [(M^{1}) (L T^{- 2}) (L)]$
$= [M L^{2} T^{- 2}]$

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Similar questions

[M^{1} L^{2} T^{- 3} A^{- 2}]

is the dimensional formula of :

Q. Dimensional formula of the product of the physical quantity P and Q is

[M^{1} L^{2} T^{- 2}]

and the dimensional formula of

\frac{P}{Q}

[M^{1} L^{0} T^{- 2}]

Q. Match List I with II and select the correct answer:

List-I	List-II
A.Spring constant	1. $M^{1} L^{2} T^{- 2}$
B.pascal	2. $M^{0} L^{0} T^{- 1}$
C.hertz	3. $M^{1} L^{0} T^{- 2}$
D.joule	4. $M^{1} L^{- 1} T^{- 2}$

Q. Match List I with List II and select the correct answer.

List - I	List - II
A) Spring constant	I) [ $M^{1} L^{2} T^{- 2}$ ]
B) Pascal	II) [ $M^{0} L^{0} T^{- 1}$ ]
C) Hertz	III)[ $M^{1} L^{0} T^{- 2}$ ]
D) Joule	IV) [ $M^{1} L^{- 1} T^{- 2}$ ]

Q. If two lines with direction cosines

l_{1}, m_{1}, n_{1}

l_{2}, m_{2}, n_{2}

intersect, then the angle between them would be -

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