The dimensional formula for pressure gradient is :

{M L}^{- 1} T^{- 2}

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M^{1} L^{- 2} T^{- 2}

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M^{1} L^{2} T^{- 2}

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M^{1} L^{- 1} T^{- 3}

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Solution

The correct option is B $M^{1} L^{- 2} T^{- 2}$
Pressure gradient $= \frac{d p}{d x}$

$p = \frac{f o r c e}{A r e a} = (k g \frac{m}{s^{2}}) (\frac{1}{m^{2}}) = M L^{- 1} T^{- 2}$

Where, $x = L (M^{0} L^{1} T^{0})$

So, $\frac{d p}{d x} = \frac{M L^{- 1} T^{- 2}}{M^{0} L^{1} T^{0}} = M L^{- 2} T^{- 2}$

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