Question

The dimensional formula for the physical quantity $\frac{E^2{\mu }_0{\epsilon }_0}{B^2}$ is (E=electric field and B= magnetic field)

• A. $L^0{M}^0{T}^0$
• B. $L^1{M}^0{T}^{-1}$
• C. $L^{-1}{M}^0{T}^1$
• D. $L^{1/2}{M}^0{T}^{-1/2}$

Answer 1

The correct option is A $L^0{M}^0{T}^0$

We know,

${\mu }_0{\epsilon }_0=\frac{1}{c^2}$

$\frac{E}{B}=c$

$\frac{E^2{\mu }_0{\epsilon }_0}{B^2}=1$

Dimension of $1=\left[M^0{L}^0{T}^0\right]$

Option $\text{A}$ is the correct answer