The dimensional formula for torque is

M L^{2} T^{- 2}

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M L^{- 1} T^{- 1}

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L^{2} T^{- 1}

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M^{2} T^{- 2} K^{- 1}

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Solution

The correct option is D $M L^{2} T^{- 2}$

$t = F r = M L T^{- 2} L = M L^{2} T^{- 2}$

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Similar questions

P V = n R T

R

[M L^{- 1} T^{- 1}]

	Column I (Units)		Column II (Dimensional formulae)
(A)	Pa s	(p)	$[M^{0} L^{2} T^{- 2} K^{- 1}]$
(B)	N m K $^{- 1}$	(q)	$[M L T^{- 3} K^{- 1}]$
(C)	J kg $^{- 1}$ K $^{- 1}$	(r)	$[M L^{- 1} T^{- 1}]$
(D)	W m $^{- 1}$ K $^{- 1}$	(s)	$[M L^{2} T^{- 2} K^{- 1}]$

M L^{- 1} T^{- 2}

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