The dimensional formula for universal gravitational constant is:

M^{1} L^{3} T^{- 2}

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M^{0} L^{2} T^{- 2}

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M^{1} L^{2} T^{- 2}

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M^{- 1} L^{3} T^{- 2}

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Solution

The correct option is B $M^{- 1} L^{3} T^{- 2}$
$F = \frac{G M_{1} M_{2}}{r^{2}}$
$G = \frac{F r^{2}}{M_{1} M_{2}} = \frac{(M L^{1} T^{- 2}) \times L^{2}}{M^{1} \times M^{1}}$ $= M^{- 1} L^{3} T^{- 2}$

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