The dimensional formula for Young's modulus is :

[M L^{- 1} T^{- 2}]

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[M^{0} L T^{- 2}]

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[M L T^{- 2}]

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[M L^{2} T^{- 2}]

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Solution

The correct option is A $[M L^{- 1} T^{- 2}]$
Young's modulus
$Y = \frac{s t r e s s}{s t r a i n}$
Dimension of $Y = \frac{M L^{- 1} T^{- 2}}{M^{0} L^{0} T^{0}}$
$= [M L^{- 1} T^{- 2}]$

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