The dimensional formula of couple is

[M L^{2} T^{- 2}]

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[M L T^{- 2}]

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[M L^{- 1} T^{- 3}]

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[M L^{- 2} T^{- 2}]

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Solution

The correct option is A $[M L^{2} T^{- 2}]$
Dimensionally couple $= T o r q u e = F o r c e \times d i s t a n c e = [M L T^{- 2}] [L] = [M L^{2} T^{- 2}]$

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M L^{- 1} T^{- 2}

\begin{matrix} List I(Physical quantity) & List II (Dimensions) A. Force & {1. T}^{- 1} B. Angular velocity & {2. MLT}^{- 2} C. Torque & {3. ML}^{- 1} T^{- 2} D. Stress & {4. ML}^{- 1} T^{- 1} {5. ML}^{2} T^{- 2} \end{matrix}

X

= \sqrt{(\frac{X}{density})}

X

M L^{- 1} T^{- 2}

M L^{- 1} T^{- 2}

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