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Byju's Answer
Standard XII
Physics
Dimensional Analysis
The dimension...
Question
The dimensional formula of electric flux is:
A
[
M
1
L
1
T
−
2
]
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B
[
M
1
L
3
T
−
3
A
−
1
]
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C
[
M
2
L
2
T
−
2
A
−
2
]
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D
[
M
1
L
−
3
T
3
A
1
]
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Solution
The correct option is
C
[
M
1
L
3
T
−
3
A
−
1
]
Electric flux
ϕ
=
∫
→
E
.
→
s
The dimension of
ϕ
=
dimension fo
E
×
dimension of
s
[
ϕ
]
=
[
M
1
L
1
T
−
2
]
[
A
T
]
−
1
[
L
2
]
=
[
M
1
L
3
T
−
3
A
−
1
]
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0
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[
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is the dimensional formula of :
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List-II
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2.
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List - I
List - II
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I) [
M
1
L
2
T
−
2
]
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II) [
M
0
L
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T
−
1
]
C) Hertz
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M
1
L
0
T
−
2
]
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−
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