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Dimensional Analysis

The dimension...

Question

The dimensional formula of electric potential is

A

[M L^{2} T^{- 3} A^{- 1}]

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B

[M^{- 1} L^{2} T^{- 2} A]

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C

[M^{- 1} L^{2} T^{- 2} A^{- 1}]

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D

[M L^{2} T^{- 2} A]

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Solution

The correct option is A $[M L^{2} T^{- 3} A^{- 1}]$
Electric potential,
$V = \frac{W}{q} = \frac{[M L^{2} T^{- 2}]}{[A T]} = [M L^{2} T^{- 3} A^{- 1}]$

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$(A) L$	$(P) [M^{0} L^{0} T^{- 2} A^{0}]$
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a) Angular velocity	e) $M L^{2} T^{- 2}$
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Q. Match the following two columns:

	Column I		Column II
A.	Electrical resistance	$1.$	$[M L^{3} T^{- 3} A^{- 2}]$
B.	Electrical potential	$2.$	$[M L^{2} T^{- 3} A^{- 2}]$
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Q. Dimensional formula

M L^{2} T^{- 3}

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