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Units and Dimensions

The dimension...

Question

The dimensional formula of modulus of rigidity is

M L T^{- 2}

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M L T^{- 1}

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M L^{2} T^{2}

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M L^{- 1} T^{- 2}

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Solution

The correct option is D $M L^{- 1} T^{- 2}$
By definition
$Modulus of rigidity = \frac{Shear stress}{Shear strain} = \frac{F / A}{x / L}$
Dimensional formula of $Modulus of rigidity are \frac{M L T^{- 2}}{L^{2}} = M L^{- 1} T^{- 2}$

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