The dimensional formula of Planck's constant is:

[M L^{2} T^{- 1}]

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[M L^{2} T^{- 2}]

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[M L^{0} T^{2}]

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[M L T^{2}]

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Solution

The correct option is A $[M L^{2} T^{- 1}]$
Energy of photon is given as
$E = h ν$
$⟹ h = \frac{E}{ν}$
Dimension of $E = [M L^{2} T^{- 2}]$
Dimension of $ν$ is $[T^{- 1}]$
Thus the dimension of plank's constant $h$ is $[M L^{2} T^{- 1}]$

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