The dimensions formula of ( velocity $)^{2} /$ radius are the same of that of :

Planck's constant

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Gravitational constant

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Dielectric constant

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None of these

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Solution

The correct option is D None of these
Dimensions formula of ( velocity $)^{2} /$ radius

$= \frac{[M^{0} L T^{- 1}]^{2}}{[M^{0} L T^{0}]} = [L T^{- 2}]$

Thus, it has the dimensions of acceleration

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