Question

The dimensions of a brush stand in the shape of a cuboid are given. Find the surface area of the box, if its top is open.

• A. 496 sq cm
• B. 696 sq cm
• C. 496 sq cm
• D. 180 sq cm

Answer 1

The correct option is B 696 sq cm

The given box is in the shape of a cuboid.

It has 6 rectangular faces: one base, one top and 4 lateral faces.

Since, the top is open, we have to find the surface area of 5 faces.


Two sides are named A and B.


Here, opposite sides are equal.

Base area = length $\times$ width

Length of the base rectangle = 12 cm

Width of the base rectangle = 8 cm

Base area = 12 $\times$ 8 = 96 sq cm



Area of side A = length $\times$ width

Length of side A = 15 cm

Width of side A = 12 cm

Area of side A = 15 $\times$ 12 = 180 sq cm

Area of the side opposite to A = 180 sq cm



Area of side B = length $\times$ width

Length of side B = 15 cm

Width of side B = 8 cm

Area of side B = 15 $\times$ 8 = 120 sq cm

Area of the side opposite to B = 120 sq cm



Total surface area = 96 + 2(180) + 2(120)

= 96 + 360 +240 = 696 sq cm

Hence, the surface area of the box = 696 sq cm.