Question

The dimensions of a cuboid are $60$cm $\times 54$ cm $\times 30$ cm. In this cuboid, if $x$ cubes with side $6$cm can be kept, then find $\frac{x}{90}$.

• A. $10$
• B. $20$
• C. $5$
• D. $15$

Answer 1

The correct option is C $5$

No. of cubes$=\frac{Vol.ofcuboid}{Vol.ofcube}$

$x=\frac{60\times 54\times 30}{6\times 6\times 6}$

$x=10\times 9\times 5$

$\frac{x}{90}=\frac{10\times 9\times 5}{90}=5$