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Standard VI

Physics

Area of Irregular Objects

The dimension...

Question

The dimensions of a cuboidal box are $2 m 50 c m \times 1 m 25 c m \times 75 c m .$ Find
(i) the area of canvas required to cover this box; and
(ii) the cost of canvas for covering the box at the rate of Rs. 4 per square metre.

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Solution

Area $= 2 (l b + l h + l h)$
$= 2 (250 \times 125 + 250 \times 75 + 125 \times 75)$
$= 2 (250 \times 200 + 125 \times 75)$
$= 2 \times 50000 + 250 \times 75$
$= 100000 + 18750$
$= 118750 c m^{2}$
$= 11.875 m^{2}$
$∴$ Cost $=$ Area $\times$ Rate
$= 11.875 \times 4 R s$
$= 47.5 R s$

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The dimensions of a cuboidal box are 2 m 50 cm× 1 m 25 cm× 75 cm. Find(i) the area of canvas required to cover this box; and(ii) the cost of canvas for covering the box at the rate of Rs. 4 per square metre.

Area =2(lb+lh+lh)=2(250×125+250×75+125×75)=2(250×200+125×75)=2×50000+250×75=100000+18750=118750cm2=11.875m2∴ Cost = Area × Rate =11.875×4Rs=47.5Rs

The dimensions of a cuboidal box are $2 m 50 c m \times 1 m 25 c m \times 75 c m .$ Find
(i) the area of canvas required to cover this box; and
(ii) the cost of canvas for covering the box at the rate of Rs. 4 per square metre.

Area $= 2 (l b + l h + l h)$
$= 2 (250 \times 125 + 250 \times 75 + 125 \times 75)$
$= 2 (250 \times 200 + 125 \times 75)$
$= 2 \times 50000 + 250 \times 75$
$= 100000 + 18750$
$= 118750 c m^{2}$
$= 11.875 m^{2}$
$∴$ Cost $=$ Area $\times$ Rate
$= 11.875 \times 4 R s$
$= 47.5 R s$