Question

The dimensions of a panel of the spacecraft is shown below.Then area of the side pannel of the spacecraft is ${\text{in}}^2$

• A. 112.5$\times {10}^9$
• B. 11.25$\times {10}^9$
• C. 1125$\times {10}^9$
• D. 11.25$\times {10}^8$

Answer 1

The correct option is B 11.25$\times {10}^9$

The panel of the spacecraft is of rectangular shape.
$\because$ Area of the rectangle = Length x Width
$\therefore$ Area of the panel
= Length of the panel $\times$ Width of the panel
= $2.5\times {10}^6\times 4.5\times {10}^3$
= $2.5\times 4.5\times {10}^{6+3}$
= $11.25\times {10}^9$

Therefore, the area of the panel is $11.25\times {10}^9{\text{in}}^2$.