The dimensions of a public park are as shown. A man goes for a walk in the morning. He walks three complete rounds along the outer perimeter and two complete rounds along the square perimeter. What is the total distance he covers during his morning walk?

1628 m

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1204 m

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1032 m

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1458 m

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Solution

The correct option is D 1458 m
Perimeter of the outer path = 70 + 32 + 75 + 20 + 14 + 75 = 286 m

Perimeter of the square = 4 x 75 = 300 m

Total distance the walks is, = 3(286) + 2(300) = 858 + 600 = 1458 m

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The dimensions of a public park are as shown. A man goes for a walk in the morning. He walks three complete rounds along the outer perimeter and two complete rounds along the square perimeter. What is the total distance he covers during his morning walk?

The correct option is D 1458 mPerimeter of the outer path = 70 + 32 + 75 + 20 + 14 + 75 = 286 m Perimeter of the square = 4 x 75 = 300 m Total distance the walks is, = 3(286) + 2(300) = 858 + 600 = 1458 m

The correct option is D 1458 m
Perimeter of the outer path = 70 + 32 + 75 + 20 + 14 + 75 = 286 m

Perimeter of the square = 4 x 75 = 300 m

Total distance the walks is, = 3(286) + 2(300) = 858 + 600 = 1458 m