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Question

The dimensions of a rectangular box are in the ratio of 2 : 3 : 4 and the difference between the cost of covering it with sheet of paper at the rates of Rs 8 and Rs 9.50 per m2 is Rs. 1248. Find the dimensions of the box.

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Solution

Suppose that the dimensions be x multiple of each other.The dimensions are in the ratio 2:3:4. Hence, length=2x mBreadth=3x mHeight=4x mSo, total surface area of the rectangular box=2×(length×breadth+breadth×height+length×height)=2×(2x×3x+3x×4x+2x×4x)=2×(6x2+12x2+8x2)=2×(26x2)=52x2 m2Also, the cost of covering the box with paper at the rate Rs 8/m2 and Rs 9.50/m2 is Rs 1248.Here, the total cost of covering the box at a rate of Rs 8/m2=8×52x2=Rs 416x2And the total cost of covering the box at a rate of Rs 9.50/m2=9.50×52x2=Rs 494x2Now, total cost of covering the box at the rate Rs 9.50/m2-total cost of covering the box at the rate Rs 8/m2=1248494x2-416x2=124878x2=1248x2=124878=16x=16=4Hence, length of the rectangular box=2×x=2×4=8 m Breadth=3×x=3×4=12 m Height=4×x=4×4=16 m

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