Question

The dimensions of a room are $(10m\times 8m\times 3.3m)$. How many men can be accommodated in this room if each man requires 3 m 3 of space?

(a) 99

(b) 88

(c) 77

(d) 75

Answer 1

Dimensions of a room are 10 m, 8 m, 3.3 m

$\therefore$ Volume of air in it =lbh

$=10\times 8\times 3.3=264m^3$

Air required for one man $=3m^3$

$\therefore$ No. of men $=\frac{264}{3}=88$