Question

The dimensions of $\frac{a}{b}$ in the equation $p=\frac{a-t^2}{bx}$, where p is pressure, x is distance and t is time, are

• A. $\left[M^{2}L{T}^{-3}\right]$
• B. $\left[M{T}^{-2}\right]$
• C. $\left[L{T}^{-3}\right]$
• D. $\left[M{L}^3{T}^{-1}\right]$

Answer 1

The correct option is B $\left[M{T}^{-2}\right]$

$p=\frac{a-t^2}{bx}$, where p-pressure, t-time
$\left[pbx\right]=\left[a\right]=\left[t^2\right]$
Hence, $\left[b\right]=\frac{\left[t^2\right]}{\left[px\right]}$
Dimensions of $\frac{a}{b}=\left[px\right]=\left[M{T}^{-2}\right]$