Question

The dimensions of $\frac{v^2}{\mu g}$ where $\mu =$ coefficient of friction, $v=$ the velocity, $g=$ acceleration due to gravity is same as that of

• A. $\frac{F}{Bq}$
• B. $\mu F$
• C. $\frac{F}{m}$
• D. None

Answer 1

Answer: (D)

None

Units of $\frac{v^2}{\mu g}$ are $m$
A) Units of $\frac{F}{Bq}=\frac{qvB}{Bq}=v$ are $m{s}^{-1}$
B) Units of $\mu F$ are $kgm{s}^{-2}$
C) Units of $\frac{F}{m}=a$ are $m{s}^{-2}$
D) Units of $qvB=F$ are $kgm{s}^{-2}$