Question

The dimensions of $\frac{(velocity{)}^2}{radius}$ are the same as that of:

• A. Planck's constant
• B. Gravitational constant
• C. Dielectric constant
• D. None of above

Answer 1

The correct option is D None of above

$\frac{V^2}{R}=\frac{{\left({LT}^{-1}\right)}^2}{L}=\frac{L^2{T}^{-2}}{L}=L{T}^{-2}$

Planck's constant $=\frac{Energy}{Y\lambda }=\frac{M{L}^2{T}^{-2}}{\frac{{LT}^{-1}}{L}}=M{L}^2{T}^{-1}$
Gravitational constant $=M^{-1}{L}^3{T}^{-2}$

Dielctric constant $=dimensionaless$