The dimensions of impulse are

[M L^{- 1} T]

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[M L T^{- 1}]

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[M L T^{- 2}]

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none of these.

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Solution

The correct option is C $[M L T^{- 1}]$

$I m p u l s e (I) = F o r c e \times T i m e$ . . . . (1)
Since, $F o r c e (F) = M a s s \times A c c e l e r a t i o n = M \times [L T^{- 2}]$
$∴$ The dimensional formula of force $= [M^{1} L^{1} T^{- 2}]$ . . . . (2)
On substituting equation (2) in equation (1) we get,
$I m p u l s e = [M^{1} L^{1} T^{- 2}] \times [T^{1}] = [M^{1} L^{1} T^{- 1}]$
Therefore, the impulse is dimensionally represented as $[M^{1} L^{1} T^{- 1}]$

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