The dimensions of magnetic field in $M, L, T$ and $C$ (coulomb) are given as

[M L T^{- 1} C^{- 1}]

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[M T^{2} C^{- 2}]

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[M T^{- 1} C^{- 1}]

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[M T^{- 2} C^{- 1}]

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Solution

The correct option is C $[M T^{- 1} C^{- 1}]$
Force $F$ acting on charge $q$ moving with velocity $v$ in magnetic field $B$ is given as $F = q v B$ thus $B = \frac{F}{q v}$
$∴ [B] = \frac{[F]}{[q v]} = \frac{M L T^{- 2}}{C \times L T^{- 1}} = [M T^{- 1} C^{- 1}]$

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The dimensions of k in the equation F = - k x (where F is force and x is displacement)

a) Thermal resistance	e) $M T^{- 3} K^{- 4}$
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[M L T^{- 1}]

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