Question

The dimensions of Planck's constant are the same as that of the

• A. linear impulse
• B. work
• C. linear momentum
• D. angular

Answer 1

The correct option is D angular

Energy of a photon, $E=h\upsilon$

where h is the Planck's constant and $\upsilon$ is the frequency.

$\therefore \left[h\right]=\frac{\left[E\right]}{\left[v\right]}=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[T^{-1}\right]}=\left[M{L}^2{T}^{-1}\right]$

Angular momentum = Moment of inertia x Angular velocity (Angular momentum)

= $\left[M{L}^2\right]\left[T^{-1}\right]=\left[M{L}^2{T}^{-1}\right]$