Question

The dimensions of $\sigma b^4$ ( σ=Stefan’s constant and b = Wien’s constant) are:

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

${\lambda }_{m}T=bor{b}^4={\lambda }_m^4{T}^4\text{a}nd\frac{energy}{area-time}=\sigma T^4\text{o}r\sigma =\frac{energy}{(area-time)T^4}\therefore \sigma b^4=\left(\frac{energy}{area-time}\right){\lambda }_m^4\text{o}r\left[\sigma b^4\right]=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[L^4\right]\left[T\right]}\left[L^4\right]=\left[M{L}^4{T}^{-3}\right]$