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Byju's Answer
Standard XII
Physics
Dimensional Analysis
The dimension...
Question
The dimensions of the coefficient of viscosity are :
A
M
L
−
1
T
−
1
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B
M
L
T
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C
M
−
1
L
−
1
T
−
1
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D
M
0
L
0
T
0
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Solution
The correct option is
A
M
L
−
1
T
−
1
Equation :
F
=
−
η
A
d
v
/
d
z
F=force, A=area,
η
= coefficient of viscosity,
d
v
is change in velocity when distance change by
d
z
[
η
]
=
[
F
]
[
d
z
]
[
A
]
[
d
v
]
=
[
M
L
T
−
2
]
[
L
]
[
L
2
]
[
L
T
−
1
]
[
η
]
=
[
M
L
−
1
T
−
1
]
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0
Similar questions
Q.
The dimension ML
−
1
T
−2
can correspond to
(a) moment of a force
(b) surface tension
(c) modulus of elasticity
(d) coefficient of viscosity
Q.
Dimensions
[
M
L
−
1
T
−
1
]
are related to
Q.
Match List I with List II and select the correct answer using the codes given the lists.
List I
List II
P. Boltzmann Constant
1
.
[
M
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2
T
−
1
]
Q. Coefficient of viscosity
2
.
[
M
L
−
1
T
−
1
]
R. Plank Constant
3
.
[
M
L
T
−
3
K
−
1
]
S. Thermal conducivity
4
.
[
M
L
2
T
−
2
K
−
1
]
Q.
A physical quantity
X
is expressed as velocity
=
√
(
X
density
)
. The dimensions of
X
are
Q.
The dimension formula of resultant when two quantities of dimensions
[
M
L
T
−
1
]
are added together, is
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