The dimensions of universal gravitational constant $G$ are :

[M L T^{- 2}]

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[M L^{3} T^{- 2}]

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[M^{- 1} L^{3} T^{- 2}]

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[M - 1 L T^{- 2}]

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Solution

The correct option is C $[M^{- 1} L^{3} T^{- 2}]$
$F = G \frac{m_{1} m_{2}}{r^{2}}$
Thus, $| F | = M L T^{- 2} = | G | \frac{M^{2}}{L^{2}}$
or, $| G | = M^{- 1} L^{3} T^{- 2}$

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Similar questions

If E, G, J and m represent energy, universal gravitational constant, angular momentum and mass respectively, then dimensions of $\frac{E J^{2}}{m^{5} G^{2}}$ are those of:

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\frac{E J^{2}}{M^{5} G^{2}}

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m_{1} a n d m_{2}

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F = \frac{G m_{1} m_{2}}{d_{2}}

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Then the dimensions of $\frac{E J^{2}}{m^{5} G^{2}}$ are

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The dimensions of universal gravitational constant G are :

The correct option is C [M−1L3T−2]F=Gm1m2r2Thus, |F|=MLT−2=|G|M2L2or, |G|=M−1L3T−2

The dimensions of universal gravitational constant $G$ are :

The correct option is C $[M^{- 1} L^{3} T^{- 2}]$
$F = G \frac{m_{1} m_{2}}{r^{2}}$
Thus, $| F | = M L T^{- 2} = | G | \frac{M^{2}}{L^{2}}$
or, $| G | = M^{- 1} L^{3} T^{- 2}$