The dimensions of voltage in terms of mass $(M)$ , length $(L)$ and time $(T)$ and ampere $(A)$ are

[M L^{2} T^{- 2} A^{- 2}]

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[M L^{2} T^{3} A^{- 1}]

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[M L^{2} T^{- 3} A^{1}]

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[M L^{2} T^{- 3} A^{- 1}]

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Solution

The correct option is C $[M L^{2} T^{- 3} A^{- 1}]$
Voltage(V) is a representation of the electric potential energy(W) per unit charge(Q).
So, $[V] = [\frac{W}{Q}] = \frac{[M L^{2} T^{- 2}]}{[A T]} = [M L^{2} A^{- 1} T^{- 3}]$

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