1
Question
The diognal of a square is 12cm long; find its area and length of one side
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Solution
Let side of square be a
by applying Pythagoras theorem
a^2+a^2= 12^2 (both length and breadth are same because it is a square)
2a^2 = 12^2
a^2= 12^2/root2
a = 12/root2
a = 6root2
By using Pythagoras theorm!
Length of one side of circle is 6√2
So area of Circle is 6√2*6√2
=72 cm²
by applying Pythagoras theorem
a^2+a^2= 12^2 (both length and breadth are same because it is a square)
2a^2 = 12^2
a^2= 12^2/root2
a = 12/root2
a = 6root2
By using Pythagoras theorm!
Length of one side of circle is 6√2
So area of Circle is 6√2*6√2
=72 cm²
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