Question

The dipole moment of chlorobenzene is $1.5D$. The dipole moment of $1,2,3,5$-tetrachlorobenzene is $x\times {10}^{-1}$. Then the value of $\frac{x}{3}$ is:

Answer 1

Dipole moment of chlorobenzene is $1.5D$. The dipole moment of 1,2,3,5 tetrachlorobenzene will remain the same.

$1.5D=x\times {10}^{-1}$

$\Rightarrow x=1.5\times 10$

$\Rightarrow x=15$

Value of $\frac{x}{3}=\frac{15}{3}=5$