Question

The dipole moment of $H_{2}O$ is 1.84D. The bond angle in $H_{2}O$ is ${104.5}^0$. The bond moment of O - H bond is (cos ${52.25}^0$ = 0.61)

• A. 1.23D
• B. 1.508D
• C. 1.642D
• D. 2.45D

Answer 1

The correct option is

B

1.508D

Dipole moment = 2 $\times$ bond moment $\times$ cos$\frac{\theta }{2}$
1.84 = 2 $\times bondmoment\times cos\frac{{52.25}^0}{2}$
1.84 = 2$\times bondmoment\times cos26.125$
1.84 = $2\times bondmoment\times 0.897$
bond moment = $\frac{1.84}{2\times 0.897}$ = 1.02