The dipole moment of HBr is 2.60×10−30C.m. and the interatomic spacing is 1.41˚A. What is the per cent ionic character of HBr?
A
11.5
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B
11
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C
10.5
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D
12
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Solution
The correct option is A11.5 Theoretical value of dipole moment of a 100% ionic character =e×d =(1.60×10−19C)(1.41×10−10m) =2.26×10−29Cm observed value of dipole moment =2.60×10−30Cm per cent ionic character =observedvaluetheoreticalvalue×100 =2.60×2.60×10−302.26×10−29×100=11.5