Question

The dipole moment of $HCN$ molecule is $2.9D$. The length of dipole in nm is:

• A. $0.0604$
• B. $0.0504$
• C. $0.345$
• D. None of these

Answer 1

The correct option is A $0.0604$

$\mu =e\times l$
$\mu =2.9D=1.9\times {10}^{-10}esu-cm$
$e=4.8\times {10}^{-10}esu$.
$\therefore l=\frac{\mu }{e}=\frac{2.9\times {10}^{-18}esu-cm}{4.8\times {10}^{-10}esu}$
$=6.04\times {10}^{-9}cm=0.0604nm$