Question

The dipole moment of hydrogen chloride is $1.03$D. Its percent ionic character is about $17\%$. Its bond distance in pm is about:

• A. $150$
• B. $127$
• C. $190$
• D. $210$

Answer 1

The correct option is B $127$

Here the percent ionic character is given as 17%

So if 'r' is the bond distance, the dipole moment of Hcl is (0.17e)r

r = $(0.17\times 1.6\times {10}^{-19}$C ) r

= $(1.03\times 3.33\times {10}^{-30}$Cm )

r = $(1.03\times 3.3356\times {10}^{-30}$Cm ) / $(0.17\times 1.6\times {10}^{-19}$C )

= So the bond distance = $1.27\times {10}^{-10}$ m

= 127 pm