Question

The dipole moment of $LiH$ is $1.964\times {10}^{29}CM$ and the intermolecular distance between $Li$ and $H$ in this molecule is $1.596$ $\dot{A}$. The percentage ionic character in molecule is(write the value to the nearest integer):

Answer 1

Calculated value of the dipole moment $=1.602\times {10}^{-19}\times 1.596\times {10}^{-10}=2.55\times {10}^{-29}$
The percentage ionic character$=\frac{2.55\times {10}^{-29}}{1.964\times {10}^{-29}}\times 100=76.82$