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Oxidation of Alcohols

The dipole mo...

Question

The dipole moments of halo compounds are in the order:

C H C l_{3} > C C l_{4} > C H_{2} C l_{2} > C H_{3} C l

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C H_{3} C l > C H C l_{3} > C H_{2} C l_{2} > C C l_{4}

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C H_{3} C l > C H_{2} C l_{2} > C H C l_{3} > C C l_{4}

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C H C l_{3} > C H_{2} C l_{2} > C H_{3} C l > C C l_{4}

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Solution

The correct option is C $C H_{3} C l > C H_{2} C l_{2} > C H C l_{3} > C C l_{4}$

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Similar questions

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}, C C l_{4}

C C l_{4}

C H_{3} C l

C H_{4} = C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}

C C l_{4}

{C H}_{4}, {C H}_{3} C l, {C H}_{2} C l_{2}, C H C l_{3}

C C l_{4}

C H_{3} C l

C H_{2} C l_{2}

C H C l_{3}

C C l_{4}

{C H}_{3} C l, {C H}_{2} {C l}_{2}, C H {C l}_{3}, C {C l}_{4}

{C H}_{3} C l > {C H}_{2} {C l}_{2} > C H {C l}_{3} > C {C l}_{4}

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