The directing power of the groups ${- N H}_{2}, - {O C H}_{3}, - C_{6} H_{5} a n d - {N O}_{2}$ follows the order __________.

{- N H}_{2} > - {O C H}_{3} > - C_{6} H_{5} > - {N O}_{2}

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{- N O}_{2} > - C_{6} H_{5} > - {O C H}_{3} > - {N H}_{2}

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- {O C H}_{3} > - {N H}_{2} > - C_{6} H_{5} > {- N O}_{2}

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- {O C H}_{3} > {- N O}_{2} > - {N H}_{2} > - C_{6} H_{5}

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Solution

The correct option is A ${- N H}_{2} > - {O C H}_{3} > - C_{6} H_{5} > - {N O}_{2}$
$- N H_{2}, - O C H_{3}, - C_{6} H_{5}$ are all ortho-para directing group. These groups when present on benzene ring, direct the second or incomming elctrophile to the ortho-para positions. These are electron donating groups, activates the aromatic ring to furthur substitution.
$- N O_{2}$ is a meta directing group, and is an electron withdrawing group, and it deactivates the benzene ring.
Therefore the order of activating groups will be:
$- N H_{2} > - O C H_{3} > - C_{6} H_{5} > - N O_{2}$

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